Possible bug in std vmod, using backtrack and tolower, 4.0.2

[Per Buer]

Hi,

On Mon, Nov 17, 2014 at 4:43 PM, T. Pascal <t_pascal at zennet.com> wrote:

> I'll have to assign the contents of the replacement group to a variable
> and then lower that variable and then substitute it back in?
>
> That's three or four vcl lines to accomplish something that seems like a
> workaround to a bug. :)
>

\1 won't work (how you expect) in string context, only in a regular
expression. Perl won't let you do this with \1 either. However, in Perl you
have $1 which I think will do what you want to. So I can understand the
confusion.

Per.

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